390x-6x^2=0

Solution for 390x-6x^2=0 equation:

390x-6x^2=0

a = -6; b = 390; c = 0;
Δ = b2-4ac
Δ = 3902-4·(-6)·0
Δ = 152100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{152100}=390$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(390)-390}{2*-6}=\frac{-780}{-12}
=+65
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(390)+390}{2*-6}=\frac{0}{-12}
=0
$